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ANOVA Testing Paper

Team A

Cynthia Calixte, Louis Nemeth, Kanika Wade, Tomarco Wilson

RES342

Jud Faurer Ph.D., MBA

March 12, 2007

ANOVA Testing Paper

At KraftMaid Cabinetry some of the marketing research of consumers is done during promotions at trade shows, while other market research of consumers is done through mail, phone, internet, and dealerships questionnaires. In all cases, the organization solicits an "intent-to-purchase" score from the consumers, with 0 being the lowest score "no intent to purchase" and 100 being the highest score "full intent to purchase" The following information is of the data collected from 120 consumers that were surveyed from the various sources; trade show, mail, phone, internet, and dealerships with the "intent to purchase". Survey scores below:

Trade Show By

Mail By Phone By Internet By Dealership

63.0 58.0 61.0 69.0 62.0

68.0 63.0 66.3 64.0 63.2

69.0 61.0 67.2 63.0 68.2

61.0 62.3 61.0 64.3 62.0

67.0 59.8 66.0 59.2 65.0

58.0 56.0 59.0 58.0 58.9

73.7 43.9 73.7 59.4 74.0

61.0 56.3 58.0 64.0 60.4

78.0 70.3 78.0 69.9 77.0

55.3 62.0 55.3 68.0 56.8

80.0 58.5 76.0 56.3 75.9

64.4 58.6 64.4 60.2 66.4

67.0 61.0 65.3 67.1 66.0

68.0 69.0 66.1 63.0 68.4

62.0 53.7 64.1 57.2 61.2

68.0 57.0 67.3 58.5 68.0

69.0 58.0 63.9 58.7 65.8

73.3 58.0 70.0 59.2 75.0

67.0 79.0 65.1 78.0 65.1

53.0 76.0 54.0 76.0 64.0

78.0 59.0 76.9 79.0 76.9

71.0 60.2 64.0 65.3 64.0

68.7 67.0 58.6 67.9 68.1

67.0 61.2 66.0 65.2 66.1

Team "A" will attempt to formulate, using an (F) test with a significance level of .01, if the means for the five different groups equal each other or if the means are not all equal. This is shown in the hypotheses statements below.

Ho: u1 = u2 = u3 =u4 = u5

H1: Not all means are the same.

The null hypothesis would state the means of the 5 different groups "intent to buy" cabinets in the future are equal. The alternate hypothesis would state that not all the means are the same. We express this as:

Step1: Ho: u1 = u2 = u3 =u4 = u5

H1: Not all means are the same.

Step 2: We will use a .01 level of significance.

Step 3: Determine the test statistic. We will follow the test statistic of the (F)

test.

Step 4: Formulate the decision rule. Using Appendix G as a frame of reference, we have determined that the critical value using (dfn) = 4 as a numerator and (dfd) = 115 as a denominator is 3.487.

Step 5: The following ANOVA table shows the results of the calculated data:

One factor ANOVA

Mean n Std. Dev

64.96 67.10 24 6.785 Trade

...

...

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